Is $y=6$ ?

(1) $y^2=36$

(2) $y^2−7y+6=0$

Answer Choices

Correct answer marked below

Statement (1) ALONE is sufficient

Statement (2) ALONE is sufficient

BOTH statements TOGETHER are sufficient

Correct

EACH statement ALONE is sufficient

Statements (1) and (2) TOGETHER are NOT sufficient

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Explanation

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Comments

PrayasAug 9

Classic trap question lol. Statement 1 gives two values so it's not enough. Statement 2 also gives two values. But together they share only one common value. Took me a sec to catch that.

IshanAug 16

you do have to solve both, but statement 2 factors nicely so its quick

AkhilJul 12

thanks, helpful!

TuanJul 30

Hmm I picked B at first because I forgot y^2=36 has two solutions. Rookie mistake.

AhmedAug 10

the negative root gets me every time too

What this question tests

What it tests

Your ability to manipulate linear and quadratic expressions, substitute unknowns, and solve equations under time pressure.

Common trap

Losing a sign when moving terms across the equals sign, or dividing both sides by a variable that could equal zero.

Is y=6y=6 y=6?(1) y2=36y^2=36y2=36(2) y2−7y+6=0y^2−7y+6=0y2−7y+6=0