Given that $|x - 4| = 10$ and $|3y - 9| = 12$ , what is the minimum possible value of $\frac{x}{y}$ ?

Correct answer marked below

\frac{-10}{9}

\frac{30}{9}

-14

Correct

-30

You can see the correct answer above. Sign in for free to unlock the complete worked solution.

Get detailed analytics, unlock full explanations, and move up difficulty tiers as you practice.

Explanation

Preview

Official Explanation

Official

Comments

BoiboiMar 20, 2025

Thank you very much!

GirirajNov 19, 2024

this helped me

AndreaApr 2, 2025

thanks!

What this question tests

Your ability to solve absolute-value equations and inequalities by considering both cases.

Dropping the absolute value bars entirely or missing that |x| = k has two solutions when k > 0.