If $g(n!) = (n!)^3$ , for all positive integers n, then what will $g(10!) - g(9!)$ equal to?

Correct answer marked below

g(1!)

g(9!)*g(3!)*10

g(9!)*20*10

g(10!)

111*9*(9!)^3

Correct

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Comments

AbhilashaApr 27, 2025

Can you explain more?

PriyadarshiniApr 27, 2025

Thank you very much!

PrayagApr 9, 2025

Can someone explain it other way?

TiborDec 23, 2024

appreciated!

AnupamaApr 12, 2025

Thankss

What this question tests

Your ability to manipulate linear and quadratic expressions, substitute unknowns, and solve equations under time pressure.

Losing a sign when moving terms across the equals sign, or dividing both sides by a variable that could equal zero.