Free Practice Question
PS · Problem Solving
555-605
Algebra
If X + Y = 7, Y + Z = 5, and Z + W = 8, then XY + WZ + XZ + YW is:
Answer Choices
Correct answer marked belowA
14
B
18
C
20
D
22
50
Correct
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Explanation
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Official Explanation
Official
To solve for XY + WZ + XZ + YW, we first need to express each variable in terms of one variable. From the equations, we have: 1) X + Y = 7, so Y = 7 - X. 2) Y + Z = 5, substituting Y gives us (7 - X) + Z = 5, which simplifies to Z = X - 2. 3) Z + W = 8, substituting Z gives us (X - 2) + W = 8, which simplifies to W = 10 - X. Now we can express XY, WZ, XZ, and YW: XY =…
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Comments
5
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A
ashrithApr 14, 2025
Amazing
S
SritamApr 26, 2025
Thanks for sharingThank you for sharing!!thanks for sharing
W
WaheedJan 11, 2025
thanks for taking time to upload it!
T
TarekMar 17, 2025
finally understood this
J
JustinMay 4, 2024
thanks
What this question tests
What it tests
Your ability to manipulate linear and quadratic expressions, substitute unknowns, and solve equations under time pressure.
Common trap
Losing a sign when moving terms across the equals sign, or dividing both sides by a variable that could equal zero.
Details
Difficulty
555-605
Type
PS
Category