How many five-digit numbers can be created using the digits 1, 2, 3, 4, and 6 (without repeating any digit), given that the digit in the unit's place must be greater than the digit in the ten's place?

Answer Choices

Correct answer marked below

54

60

Correct

20

2 × 4!

120

See the full step-by-step explanation

You can see the correct answer above. Sign in for free to unlock the complete worked solution.

Track your performance and improve

Get detailed analytics, unlock full explanations, and move up difficulty tiers as you practice.

Start for free Sign in

Explanation

Preview

Official Explanation

Official

The total number of five-digit numbers that can be formed using the digits 1, 2, 3, 4, and 6 (without repeating any digit) is calculated as 5 × 4 × 3 × 2 × 1 = 5! = 120. Out of these combinations, in half of the cases, the unit's digit will be greater than the ten's digit, while in the other half, it will be smaller. For instance, if we consider three digits 1, 2, and 3, the…

Read the full explanation

Create free account Sign in

Comments

NathanJun 28, 2024

thanksss

What this question tests

What it tests

Your fluency with the order of operations, fractions, decimals, and basic number sense — the foundation every quant question leans on.

Common trap

Applying the order of operations out of sequence or rounding intermediate values before the final step.