Free Practice Question
PS · Problem Solving
505-555
Combinations
An identification code consists of five symbols: A1, A2, B1, B2, B3. The first two symbols must be selected from the 26 letters of the English alphabet, while the last three symbols must be chosen from 10 digits. (Repetition of letters and digits is permitted.) How many unique identification codes can be formed?
Answer Choices
Correct answer marked belowA
1,757,600
676,000
Correct
C
468,000
D
1,676
E
82
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Explanation
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Official Explanation
Official
The first two symbols A1 and A2 can each be any of the 26 letters of the English alphabet (with repetition allowed), which gives us: 26 x 26 = 676. The last three symbols B1, B2, and B3 can each be any of the 10 digits (with…
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G
GiovannaJul 4, 2024
Amazing
T
TarekMar 26, 2025
Greatt
What this question tests
What it tests
Whether you can count arrangements and selections correctly — permutations vs. combinations.
Common trap
Overcounting: treating a selection as ordered when order does not matter, or forgetting to divide by duplicates.
Details
Difficulty
505-555
Type
PS
Category