If there are y teams and each team competes against every other team once, how many games would be played if there was one fewer team, resulting in only half as many games? What is the value of y?

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Official Explanation

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When there are 'Y' teams, the total number of games played is calculated as follows: 1 + 2 + 3 + ... + (Y-1) = (Y-1)(1 + (Y-1))/2 = Y(Y-1)/2. If there are 'Y-1' teams, the total number of games played is: 1 + 2 + 3 + ... + (Y-2) = (Y-2)(1 +…

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Comments

HarshiSep 12, 2024

thanks!

BriannaMay 5, 2024

thanks a lot

What this question tests

What it tests

Whether you can count arrangements and selections correctly — permutations vs. combinations.

Common trap

Overcounting: treating a selection as ordered when order does not matter, or forgetting to divide by duplicates.