Free Practice Question
PS · Problem Solving
705-805
Combinations
Will must choose a 3-character computer password, consisting of 1 letter from the alphabet and 2 distinct digits, in any order. From how many different passwords can Will choose?
Answer Choices
Correct answer marked belowA
390
B
2,340
C
4,680
7,020
Correct
E
14,040
See the full step-by-step explanation
You can see the correct answer above. Sign in for free to unlock the complete worked solution.
Track your performance and improve
Get detailed analytics, unlock full explanations, and move up difficulty tiers as you practice.
Explanation
Preview
Official Explanation
Official
Take the task of creating a password and break it into stages.
Stage 1: Select the one letter to be used in the code
There are 26 letters from which to choose, so we can complete this stage in 26 ways.
Stage 2: Select the two digits to be used in the code
Since the order in which we select the two digits does not matter, we can use combinations. We can select 2 digits from 10 digits in ways (45 ways). So we can complete stage 2 in 45 ways.
NOTE: We now have the 3 characters to be used in the code. At this point, we need to arrange those 3 characters.…
Stage 1: Select the one letter to be used in the code
There are 26 letters from which to choose, so we can complete this stage in 26 ways.
Stage 2: Select the two digits to be used in the code
Since the order in which we select the two digits does not matter, we can use combinations. We can select 2 digits from 10 digits in ways (45 ways). So we can complete stage 2 in 45 ways.
NOTE: We now have the 3 characters to be used in the code. At this point, we need to arrange those 3 characters.…
Read the full explanation
Sign in for free to see the complete step-by-step solution to this question.
Comments
Sign in to join the discussion
No comments yet
Be the first to share your thoughts and help others understand it better.
Sign in to commentWhat this question tests
What it tests
Whether you can count arrangements and selections correctly — permutations vs. combinations.
Common trap
Overcounting: treating a selection as ordered when order does not matter, or forgetting to divide by duplicates.
Details
Difficulty
705-805
Type
PS
Category