A vehicle journeyed from Seattle to Portland in 5 hours at an average speed of x miles per hour. If the vehicle returned along the same path at an average speed of y miles per hour, what was the total time taken for the round trip, in minutes?
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Thankss
Thank you very much!
thanks, this one clicked pretty fast once I realized the trip out is 5 hours so distance is 5x.
yeah same, the outbound distance basically does all the work for you
wait why is the return time 5x/y and not 5y/x? i keep flipping these
return time = distance/speed. distance is still 5x, speed is y, so it's 5x/y. the x goes on top because it's in the distance.
ohh that makes sense, i was plugging the wrong one into the denominator. thanks!
small thing but the whole thing has to be multiplied by 60 since it asks for minutes, almost picked B because of that lol
easy one for sure, just make sure you don't leave it in hours. got A without too much trouble.
What it tests
Your application of distance = rate × time to trains, boats, and commuters, including relative speed.
Common trap
Mixing units (miles per hour vs. minutes) or averaging speeds — average speed is total distance over total time.