During a road trip in his camper, Tom covered a total of y miles. He maintained an average speed of 60 miles per hour for the whole journey, except for a 15-mile stretch where he could only go 30 miles per hour due to roadwork.
What percentage more was his travel time for the y-mile journey compared to what it would have been if he had traveled at 60 miles per hour the entire time?

Answer Choices

Correct answer marked below

\frac{60}{y}

\frac{1000}{y}

\frac{1500}{y}

Correct

\frac{2000}{y}

\frac{2250}{y}

See the full step-by-step explanation

You can see the correct answer above. Sign in for free to unlock the complete worked solution.

Track your performance and improve

Get detailed analytics, unlock full explanations, and move up difficulty tiers as you practice.

Start for free Sign in

Explanation

Preview

Official Explanation

Official

During a road trip in his camper, Tom covered a total of y miles. He maintained an average speed of 60 miles per hour for the whole journey, except for a 15-mile stretch where he could only go 30 miles per hour due to roadwork. To find the percentage increase in travel time, we first calculate the time taken for the entire trip at 60 mph, which is

\frac{y}{60}

hours. The time for the 15-mile section at 30 mph is

\frac{15}{30} = 0.5

hours, and…

Read the full explanation

Create free account Sign in

Comments

manishaMar 2, 2025

thanks

JoelMay 26, 2024

Great!

kaigeFeb 28, 2024

thank you very much!

What this question tests

What it tests

Your application of distance = rate × time to trains, boats, and commuters, including relative speed.

Common trap

Mixing units (miles per hour vs. minutes) or averaging speeds — average speed is total distance over total time.