On a company retreat, the employees are divided into teams for a scavenger hunt. If the employees can be divided into 4 equal teams or 6 equal teams, what is the lowest possible number of employees?
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This one was pretty straightforward — just find the LCM of 4 and 6 and you're done. Took me like 20 seconds.
Yeah, the wording is basically telling you to look for the least common multiple.
Wait, why isn't 6 the answer? I get that 6/6=1 team but 6/4 doesn't work... I almost picked A before catching that.
Haha I made the same mistake at first, the phrase "or" threw me off.
Is the key here that we need a number divisible by both 4 and 6, not just one of them? That's the part I had to reread twice.
Exactly, the "or" means either division must work, so it has to satisfy both.
Solid 500-level problem. Nothing tricky once you spot the LCM setup, though the choices are close enough that a careless person might grab 12 vs 24.
What it tests
Your understanding of divisibility rules, least common multiples, and greatest common factors.
Common trap
Forgetting that 1 is not prime and that every integer divides 0.