Free Practice Question
PS · Problem Solving
655-705
Divisibility/Multiples/Factors
Determine how many integers from 1 to 1000 inclusive possess exactly 3 positive divisors.
Answer Choices
Correct answer marked below11
Correct
B
16
C
18
D
22
E
25
See the full step-by-step explanation
You can see the correct answer above. Sign in for free to unlock the complete worked solution.
Track your performance and improve
Get detailed analytics, unlock full explanations, and move up difficulty tiers as you practice.
Explanation
Preview
Official Explanation
Official
This problem revolves around prime numbers. To have exactly 3 divisors, a number must be expressed in the form of X = , where p is a prime number. This is because a prime number has two divisors: itself and 1. Consequently, the square of a prime number…
Read the full explanation
Sign in for free to see the complete step-by-step solution to this question.
Comments
1
Sign in to join the discussion
H
HiyoriJan 17, 2024
Amazing
What this question tests
What it tests
Your understanding of divisibility rules, least common multiples, and greatest common factors.
Common trap
Forgetting that 1 is not prime and that every integer divides 0.
Details
Difficulty
655-705
Type
PS
Category