Free Practice Question
PS · Problem Solving
705-805
Divisibility/Multiples/Factors
If a, b, and c are consecutive integers, where 10 < a < b < c, which of the following could be the remainder when is divided by b?
Answer Choices
Correct answer marked belowA
I only
B
II only
C
III only
I and II only
Correct
E
I and III only
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Explanation
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Official Explanation
Official
We have three consecutive integers a, b, and c with 10 < a < b < c. So we can write a = b - 1 and c = b + 1.
We want the remainder when is divided by b.
When you expand this expression, all terms except the last one will be multiples of b and thus will be divisible by b. The last one will be .
Hence, the question essentially boils down to finding the remainder when is divided by b.
If b is odd, then b + 1 is even, so . And 1 divided by b will give the remainder of 1.
If b is even, then b + 1 is odd, so . And -1 divided by b will give the remainder of b - 1. For example, -1 divided by 20 gives the remainder of 20 - 1 = 19.
Answer: D.
P.S. The process for finding the remainder when dividing a negative integer by a positive integer follows the same principles as when dividing a positive integer by a positive integer.…
We want the remainder when is divided by b.
When you expand this expression, all terms except the last one will be multiples of b and thus will be divisible by b. The last one will be .
Hence, the question essentially boils down to finding the remainder when is divided by b.
If b is odd, then b + 1 is even, so . And 1 divided by b will give the remainder of 1.
If b is even, then b + 1 is odd, so . And -1 divided by b will give the remainder of b - 1. For example, -1 divided by 20 gives the remainder of 20 - 1 = 19.
Answer: D.
P.S. The process for finding the remainder when dividing a negative integer by a positive integer follows the same principles as when dividing a positive integer by a positive integer.…
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What it tests
Your understanding of divisibility rules, least common multiples, and greatest common factors.
Common trap
Forgetting that 1 is not prime and that every integer divides 0.
Details
Difficulty
705-805
Type
PS
Category