Free Practice Question
PS · Problem Solving
705-805
Divisibility/Multiples/Factors
If the greatest integer k for which is a factor of n! is 8, what is the largest possible value of p so that is a factor of n!?
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Official Explanation
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If the greatest integer k for which is a factor of n! is 8, we need to find the largest possible value of p so that is a factor of n!.
We can solve by examining factorials:
- has one
- has two
- has four
- has five
- has six
- has eight
- also has eight
- has nine
Given that the greatest integer k for which is a factor of is 8, cannot be (since that would give k=9). Therefore, will be (or a factorial between 18! and 20!). To maximize the value of p for , we take the largest possible n! that still satisfies k=8, which is .…
We can solve by examining factorials:
- has one
- has two
- has four
- has five
- has six
- has eight
- also has eight
- has nine
Given that the greatest integer k for which is a factor of is 8, cannot be (since that would give k=9). Therefore, will be (or a factorial between 18! and 20!). To maximize the value of p for , we take the largest possible n! that still satisfies k=8, which is .…
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What it tests
Your understanding of divisibility rules, least common multiples, and greatest common factors.
Common trap
Forgetting that 1 is not prime and that every integer divides 0.
Details
Difficulty
705-805
Type
PS
Category