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PS · Problem Solving

505-555

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Evaluate the expression $(3^2-1)(3^2+1)(3^4+1)(3^8+1)=$

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3^{16} - 1

Correct

B

3^{16} + 1

C

3^{32} - 1

D

3^{128} - 1

E

3^{16}(3^{16}-1)

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Official Explanation

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To simplify

(3^2-1)(3^2+1)(3^4+1)(3^8+1)

, we can use the difference of squares:

(a-b)(a+b)=a^2-b^2

.…

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S

SahajmeetJun 22, 2024

thankss

S

SusieMar 14, 2025

thanks

Evaluate the expression $(3^2-1)(3^2+1)(3^4+1)(3^8+1)=$

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Evaluate the expression (32−1)(32+1)(34+1)(38+1)=(3^2-1)(3^2+1)(3^4+1)(3^8+1)=(32−1)(32+1)(34+1)(38+1)=

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Evaluate the expression $(3^2-1)(3^2+1)(3^4+1)(3^8+1)=$