Two integers A and B are such that and . Find the relation between A and B.
Answer Choices
Correct answer marked belowSee the full step-by-step explanation
You can see the correct answer above. Sign in for free to unlock the complete worked solution.
Track your performance and improve
Get detailed analytics, unlock full explanations, and move up difficulty tiers as you practice.
Unlock the full explanation
Create a free account to reveal the correct answer, see the step-by-step explanation, and start tracking your GMAT progress.
Wait, B is a geometric series right? Sum from 2^0 to 2^64... that's 2^65 - 1. So B = 2^65 - 1 and A = 2^65, meaning A is bigger by 1. Took me a sec to see the pattern, but once you recognize the sum it's straightforward.
Yeah exactly, the formula is 2^(n+1) - 1 for sum up to 2^n. Classic trap though, I initially thought B might be larger.
Same here, I almost picked B before realizing the sum formula gives one less than the next power.
This is a 705+ question? Seems more like a 600-level pattern recognition thing. Maybe I'm missing a trap...
I think the difficulty comes from having to recall the geometric series sum formula quickly under time pressure. But yeah, if you know it, it's not that bad.
Can someone explain why the sum 2^64 + ... + 2^0 equals 2^65 - 1? I get that it's a geometric series but I always mess up the formula.
Multiply both sides by 2 and subtract, or just use a = 1, r = 2, n = 65 terms. The result is (2^65 - 1)/(2-1).
Or think of it like binary: 111...1 (65 ones) is 2^65 - 1.
The choices are tricky because D and E bring in 2^64, which is way bigger than 1. If you don't simplify B, you might think the difference is huge. Good question to test if you actually simplify.
What it tests
Your grasp of exponent rules — multiplying and dividing powers, power-of-a-power, and negative/zero exponents.
Common trap
Adding exponents when multiplying bases that have the same exponent, or confusing (x^a)^b with x^(a·b).