Free Practice Question

PS · Problem Solving

705-805

Functions

If $f(x) = 90x^2 + 20x + 1$ , then find the sum of the digits of $f(11111)$ ?

Answer Choices

Correct answer marked below

A

10

11

Correct

C

101

D

111

E

112

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Explanation

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Official Explanation

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f(x)=90x^2+20x+1

f(x)=10x(9x+2)+1=10x(9x+1+1)+1

f(11111)=(10 \times 11111) \times ((9 \times 11111)+1+1)+1

f(11111)=(111110) \times (99999+1+1)+1=(111110) \times (100000+1)+1

…

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If $f(x) = 90x^2 + 20x + 1$ , then find the sum of the digits of $f(11111)$ ?

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If f(x)=90x2+20x+1f(x) = 90x^2 + 20x + 1f(x)=90x2+20x+1, then find the sum of the digits of f(11111)f(11111)f(11111)?

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What it tests

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If $f(x) = 90x^2 + 20x + 1$ , then find the sum of the digits of $f(11111)$ ?