For which value of $x$ does $g(x)$ reach its minimum, given that $g(x) = x^2 + 4x + 4$ for all real numbers $x$ ?

Answer Choices

Correct answer marked below

-2

Correct

-3

-4

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Explanation

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Official Explanation

Official

To find the maximum of g(x) = x^2 + 4x + 4, we can rewrite it as g(x) = (x + 2)^2.

Evaluating at the options:

A. 1 gives g(1) = (1 + 2)^2 = 3^2 = 9.

B. 0 gives g(0) = (0 + 2)^2 = 2^2 = 4.…

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Comments

NainaaSep 2, 2024

got this wrong on my practice

AmaanApr 9, 2024

Good question

What this question tests

What it tests

Your ability to evaluate and compose functions, including unusual defined operations.

Common trap

Applying function operations in the wrong order or ignoring domain restrictions.

For which value of xxx does g(x)g(x)g(x) reach its minimum, given that g(x)=x2+4x+4g(x) = x^2 + 4x + 4g(x)=x2+4x+4 for all real numbers xxx?