Given that A < 0, 15 < B < 35, and 60 < C < 90, what is the order of the reciprocals 1/A, 1/B, and 1/C?

Correct answer marked below

1/A < 1/B < 1/C

1/A < 1/C < 1/B

Correct

1/C < 1/A < 1/B

1/C < 1/B < 1/A

1/B < 1/C < 1/A

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Explanation

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Official Explanation

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Since A is negative, it is the smallest value, making 1/A the largest reciprocal. For B and C, since…

Comments

NainikaFeb 29, 2024

thanks!

HiyoriFeb 26, 2025

Thanks for sharingThank you for sharing!!thanks for sharing

TrucAug 12

This one tripped me up ngl. I plugged in B=20 and C=80 and it finally clicked.

KaasMay 14

is 1/A always less than 1/B here? like no matter how big A is?

BenjaminMay 22

yep, since A<0 the reciprocal is negative, and B,C are positive so their reciprocals are positive. negative < any positive.

What this question tests

Your ability to solve and combine linear inequalities and reason about ranges of values.

Failing to flip the inequality sign when multiplying or dividing by a negative, or missing an inclusive/exclusive endpoint.