Miguel is mixing up a salad dressing. Regardless of the number of servings, the recipe requires that $5/8$ of the finished dressing mix be olive oil, $1/4$ vinegar, and the remainder an even mixture of salt, pepper and sugar. If Miguel accidentally doubles the vinegar and forgets the sugar altogether, what proportion of the botched dressing will be olive oil?

Wait, so the original mix is 5/8 oil, 1/4 vinegar, and the remaining 1/8 is split equally among salt, pepper, and sugar? That means each of those is 1/24. Then if he doubles the vinegar and skips sugar, the new total isn't 1 anymore. That's the trap I fell into at first—I kept the oil at 5/8 and just changed the others. Gotta recalculate the whole thing.

This one is tricky because the 'even mixture of salt, pepper and sugar' means each is 1/3 of the remainder. The remainder is 1 - 5/8 - 1/4 = 1/8, so each is 1/24. Then doubling vinegar gives 1/2, no sugar, salt and pepper stay 1/24 each. So new total = 5/8 + 1/2 + 2/24 = 5/8 + 1/2 + 1/12. Common denominator 24: 15/24 + 12/24 + 2/24 = 29/24. Oil proportion = (15/24)/(29/24) = 15/29. Answer A. But I almost missed the salt and pepper still being there.

Is this really 655-705? I thought it was pretty straightforward once you set up the fractions. Maybe the tricky part is realizing the total changes. But yeah, answer is A.

I got E (13/27) because I accidentally doubled the salt and pepper too. Gotta read carefully: 'accidentally doubles the vinegar and forgets the sugar altogether'—only vinegar changes, sugar removed, salt and pepper unchanged.