Every morning, Mia has one piece of fruit for breakfast. She chooses apples on five days of the week and pears on the remaining two days. Ethan also has one piece of fruit each morning. If he selects apples three days a week and pears the other four days, what is the probability that they will have the same type of fruit today?

Answer Choices

Correct answer marked below

\frac{15}{49}

\frac{20}{49}

\frac{23}{49}

Correct

\frac{30}{49}

\frac{35}{49}

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Explanation

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Official Explanation

Official

To find the probability that Mia and Ethan eat the same type of fruit today, we calculate the probability that both eat apples or both eat pears.

The probability that both Mia and Ethan eat apples is given by:

Probability(Mia eats apples) AND Probability(Ethan eats apples) =

\frac{5}{7} * \frac{3}{7} = \frac{15}{49}

.

The probability that both Mia and Ethan eat pears is:…

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Comments

AdyantSep 7, 2024

Great explanation

Bish0pAug 11, 2024

thanksss

What this question tests

What it tests

Your ability to compute probabilities of single and compound events, including 'at least one' questions.

Common trap

Forgetting to use the complement for 'at least one', or treating dependent events as independent.