Free Practice Question
PS · Problem Solving
505-555
Probability
In a group photo, 6 individuals are to be arranged in two rows. The first row will have 2 people, and the second row will have 4. Among the group are Anna and Ben. If the positions are randomly assigned, what is the probability that Anna is placed in the rightmost spot of the front row, while Ben is positioned somewhere in the back row? Express your answer in terms of factorials.
Answer Choices
Correct answer marked belowA
B
Correct
D
E
See the full step-by-step explanation
You can see the correct answer above. Sign in for free to unlock the complete worked solution.
Track your performance and improve
Get detailed analytics, unlock full explanations, and move up difficulty tiers as you practice.
Explanation
Preview
Official Explanation
Official
To solve the problem, we need to determine the probability that Anna is placed in the rightmost spot of the front row while Ben is positioned somewhere in the back row. Here's a step-by-step explanation:
Step 1: Total Number of Arrangements
First, we calculate the total number of ways to arrange the 6 individuals in two rows:
- Front row: 2 spots
- Back row: 4 spots
The total number of ways to arrange 6 people in these spots is the number of permutations of 6 distinct positions:
Step 2: Fix Anna in the Rightmost Front Spot
We want Anna to be in the rightmost spot of the front row. This fixes Anna's position:
- Front row: [Any person, Anna]
The number of ways to arrange the remaining 5 people (excluding Anna) in the remaining 5 spots is:
However, since Anna's position is fixed, we don't need to consider her in the permutation of the remaining spots.
Step 3: Ensure Ben is in the Back Row
Now, we need Ben to be in one of the 4 back row spots.
- Back row: 4 spots
- Front row: 1 spot remaining (since Anna occupies the rightmost front spot)
The probability that Ben is placed in the back row is the number of back row spots divided by the remaining spots after placing Anna:
Step 4: Calculate the Desired Arrangements
The number of favorable arrangements is the number of ways to place Ben in the back row multiplied by the number of ways to arrange the remaining 4 people (excluding Anna and Ben) in the remaining 4 spots:…
Step 1: Total Number of Arrangements
First, we calculate the total number of ways to arrange the 6 individuals in two rows:
- Front row: 2 spots
- Back row: 4 spots
The total number of ways to arrange 6 people in these spots is the number of permutations of 6 distinct positions:
Step 2: Fix Anna in the Rightmost Front Spot
We want Anna to be in the rightmost spot of the front row. This fixes Anna's position:
- Front row: [Any person, Anna]
The number of ways to arrange the remaining 5 people (excluding Anna) in the remaining 5 spots is:
However, since Anna's position is fixed, we don't need to consider her in the permutation of the remaining spots.
Step 3: Ensure Ben is in the Back Row
Now, we need Ben to be in one of the 4 back row spots.
- Back row: 4 spots
- Front row: 1 spot remaining (since Anna occupies the rightmost front spot)
The probability that Ben is placed in the back row is the number of back row spots divided by the remaining spots after placing Anna:
Step 4: Calculate the Desired Arrangements
The number of favorable arrangements is the number of ways to place Ben in the back row multiplied by the number of ways to arrange the remaining 4 people (excluding Anna and Ben) in the remaining 4 spots:…
Read the full explanation
Sign in for free to see the complete step-by-step solution to this question.
Comments
Sign in to join the discussion
No comments yet
Be the first to share your thoughts and help others understand it better.
Sign in to commentWhat this question tests
What it tests
Your ability to compute probabilities of single and compound events, including 'at least one' questions.
Common trap
Forgetting to use the complement for 'at least one', or treating dependent events as independent.
Details
Difficulty
505-555
Type
PS
Category