From a standard deck of 52 cards, 4 cards are drawn one after another without putting any back. What is the probability of drawing, in sequence, a diamond, a spade, a heart, and a club?

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Correct answer marked below

\frac{13}{52}⋅\frac{13}{51}⋅\frac{13}{50}⋅\frac{13}{49}

Correct

\frac{13}{51}⋅\frac{12}{50}⋅\frac{11}{49}⋅\frac{10}{48}

\frac{4}{52}⋅\frac{4}{51}⋅\frac{4}{50}⋅\frac{4}{49}

\frac{13}{52}⋅\frac{13}{52}⋅\frac{13}{52}⋅\frac{13}{52}

\frac{13}{52}⋅\frac{12}{52}⋅\frac{11}{52}⋅\frac{10}{52}

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Official Explanation

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In a standard deck of 52 cards, there are 13 cards of each suit. To find the probability of drawing the cards in the specified order, we start with the first card, which is a diamond. The probability of drawing a diamond first is

\frac{13}{52}

. After drawing a diamond, we move to the next card, which is a spade. The number of spades…

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Comments

JahnaviMay 25, 2024

Greatt

SuhaniMay 15, 2025

One answer was incorrect and fixed. Thanks for reporting.

RaymondAug 11, 2024

thanksss

What this question tests

What it tests

Your ability to compute probabilities of single and compound events, including 'at least one' questions.

Common trap

Forgetting to use the complement for 'at least one', or treating dependent events as independent.