If x > 0, which of the following is equal to 32x^5 ?

Free Practice Question

PS · Problem Solving

sub-505

Roots

If $x > 0$ , which of the following is equal to $\sqrt{32x^{5}}$ ?

Correct answer marked below

2x \sqrt{8x^{4}}

16x \sqrt{2x}

4x^{2} \sqrt{2x}

Correct

8x^{2} \sqrt{2x^{2}}

8x^{4} \sqrt{4x}

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Explanation

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Comments

MariahMay 25

thanks, this one was pretty quick once you split up the 32 and the x^5

KashekaaAug 17

wait why does x have to be positive? is it just so we don't worry about absolute values?

AniketAug 23

yeah basically, since x>0 you can pull x's out of the root without the absolute value stuff

NikodemApr 17

got C but B tripped me up for a sec, kept trying to leave a 2x inside instead of 2x^5.

MitaleeApr 19

same, i always forget to add the leftover exponent back in lol

What this question tests

Your handling of square and higher roots, including simplifying radicals.

Forgetting the ± when taking a square root to solve an equation, or assuming √(a²) = a.