If 40 workers complete 1/3 of a room's area in 90 days, how many days would 100 workers need to finish 1/4 of the leftover room area, assuming all workers operate at the same efficiency?

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To solve this, we can use a similar approach with a table. First, we calculate the total work done in terms of man-days. The total man-days for the first part is given by 90 days multiplied by 40 workers, which equals 3600 man-days. This corresponds to 1/3 of the room, so the total room area can be represented as 3600 man-days multiplied by 3, resulting in 10800 man-days for the entire room. Each worker contributes 1/10800…

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JJun 3, 2024

thanks a lot

What this question tests

What it tests

Your ability to combine individual work rates, usually by working with the fraction of a job completed per unit of time.

Common trap

Adding the times instead of the rates, or forgetting to take the reciprocal when combining rates.