A metal mixture has a total weight of 30 ounces and consists of 60 percent silver. How many ounces of pure silver need to be added to adjust the mixture to contain 80 percent silver?

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Official Explanation

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To solve this problem, we will follow a similar approach as before. First, we need to determine the weight of the part of the mixture that remains unchanged. The non-silver portion is 40% of 30 ounces, which is calculated as follows: 0.4 * 30 = 12 ounces. Next, we find the new total weight of the mixture.…

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Comments

BalOct 19, 2024

Greatt

MystiqueJul 1, 2024

thanks!

What this question tests

What it tests

Your ability to reason about weighted averages and the composition of mixtures.

Common trap

Averaging the percentages of two solutions without weighting by their volumes.