What is the amount of pure iron that needs to be mixed with 510 grams of pure copper to form an alloy that consists of 85% copper?

Answer Choices

Correct answer marked below

30 grams

45 grams

75 grams

90 grams

Correct

150 grams

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Official Explanation

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To determine how much pure iron is required to create an alloy that is 85% copper, we start with 4510 grams of copper. This amount represents 85% of the total weight of the alloy. We can set up the equation: 510 = (85/100) *…

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Comments

SarthakJan 26, 2025

still struggling with these types of problems

YousraSep 5, 2024

thankss

What this question tests

What it tests

Your ability to reason about weighted averages and the composition of mixtures.

Common trap

Averaging the percentages of two solutions without weighting by their volumes.